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Чому дорівнює reg [ 2 : 0 ] c після виконання c <= (a == b) ? 1'b1 : 1'b0 ...

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Чому дорівнює reg [2:0] c після виконання c <= (a == b) ? 1'b1 : 1'b0, якщо a = 3'd5, b = 3'd2.

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