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Study the following code snippet and choose the correct value of iY that the ShowMessage() function will output.
var iX, iY: integer;
begin iX := (2 * 8 / 4) ;
case iX of 1, 3, 7 : begin if (iX >= 3) and (iX <= 7) then iY := 1 else if (iX > 1) and (iX < 3) then iY := 2 else iY := 3; end;
0, 2, 8 : begin if (iX >= 2) and (iX <= 8) then iY := 4 else if (iX > 0) and (iX < 2) then iY := 5 else iY := 6; end;4, 5, 6 : begin if (iX > 5) and (iX < 6) then iY := 7 else if (iX >= 4) and (iX < 5) then iY := 8 else iY := 9; end;ShowMessage('The value of iY is ' + IntToStr(iY));end;