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El área limitada por las funciones f ( x ) = - 2 x 2 + 3 2 f(x)=-2x^2+\frac{3}{2...
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El área limitada por las funcionesf(x)=-2x2+32f(x)=-2x^2+\frac{3}{2}yg(x)=1-x2g(x)=\sqrt{1-x^2}, en el intervalo[-32,32][\frac{-\sqrt{3}}{2},\frac{\sqrt{3}}{2}]vale:
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