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Respecte a la Pràctica 2 , si E o Cl 2 /Cl - = 1,36V i E o Br 2 /Br - = 1,0...

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Respecte a la Pràctica 2, si Eo Cl2/Cl- = 1,36V i Eo Br2/Br- = 1,06V, podem dir que:

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