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Consider the following MIPS assembly code which implements a FOR loop to find t...
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Consider the following MIPS assembly code which implements a FOR loop to find the sum of all the elements of an array of 10 integers, of which the base address is loaded in register $a0. The address of each instruction is mentioned next to the respective instruction.
Instruction Address | Instruction |
0x80010014 | addi $t0, $zero, 10 |
0x80010018 | li $t1, 0 |
0x8001001C | li $v0, 0 |
0x80010020 | loop: beq $t0, $t1, exit |
0x80010024 | lw $t2, 0($a0) |
0x80010028 | add $v0, $v0, $t2 |
0x8001002C | addi $t1, $t1, 1 |
0x80010030 | addi $a0, $a0, 4 |
0x80010034 | j loop |
0x80010038 | exit: addi $a0, $a0, -40 |
(a) beq $t0, $t1, exit
31 | 30 | 29 | 28 | 27 | 26 | 25 | 24 | 23 | 22 | 21 | 20 | 19 | 18 | 17 | 16 | 15 | 14 | 13 | 12 | 11 | 10 | 9 | 8 | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 |
(b) j loop
31 | 30 | 29 | 28 | 27 | 26 | 25 | 24 | 23 | 22 | 21 | 20 | 19 | 18 | 17 | 16 | 15 | 14 | 13 | 12 | 11 | 10 | 9 | 8 | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 |