Vyřešte nerovnici \frac{-6x-6}{3x-9}\geq -1.

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Vyřešte nerovnici

\frac{-6x-6}{3x-9}\geq -1.

(-\infty,-1\rangle\cup(3,\infty)

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\langle-5, 3)

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(3,\infty)

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(-\infty, 3)

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(-\infty,-5\rangle\cup(3, \infty)

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\langle -1,0)

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