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On a 64-bit architecture, with const char* s1 = "12345"; char tab1[] = "43210"...

✅ The verified answer to this question is available below. Our community-reviewed solutions help you understand the material better.

On a 64-bit architecture, with

const char* s1 = "12345";
char tab1[] = "43210";

and

void f(const char* s2, char tab2[]);

which of the following statements are true?

Statements involving s1 and tab1 are (of course) considered in the scope of s1 and tab1;

statements involving s2 and tab2 are considered in the body of f() and evaluated during the call f(s1, tab1).

Penalty for wrong ticks.

strlen(s1) == strlen(tab1)

✅

sizeof(s2) == strlen(s2)

sizeof(tab1) == strlen(tab1)

sizeof(s2) == sizeof(tab2)

✅

sizeof(tab2) == strlen(tab2)

sizeof(s1) == strlen(s1)

None of the others, some code does not compile or does not run properly.

sizeof(s1) == sizeof(tab1)

strlen(s2) == strlen(tab2)

✅

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