Let us suppose that we have a measurement setup
with the lock-in amplifier. In addition to the AC signal at the probe
frequency, there is a DC voltage present on the lock-in input. How does the DC
voltage manifest in the detected lock-in signal?

Question

Answer

It does not manifest in any way (as long as the
input does not go to overload).

Answer

The DC voltage will appear in the Y quadrature.

Answer

The DC voltage will appear in the X quadrature.

Crowdly

Let us suppose that we have a measurement setup with the lock-in amplifier. In a...

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