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2BrCl (g) ⇌ Cl 2  (g) + Br 2  (g) For this reaction, the equilibrium consta...

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2BrCl (g) ⇌ Cl2 (g) + Br2 (g)

For this reaction, the equilibrium constant, K = 0.0172. If, after equilibrium has been reached, the partial pressure of BrCl is decreased the result will be:

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