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El área de las regiones que limita la función f ( x ) = - 2 x 2 + 3 2 f(x)=-2x^2...

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El área de las regiones que limita la funciónf(x)=-2x2+32f(x)=-2x^2+\frac{3}{2}con el eje de abscisas en el intervalo[-2,2][-2,2]vale:

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