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Which of the following formulas are equivalent to ((¬x → (y ∨ z)) ↔ (x ∨ ¬y)) ?
((¬x → (y ∨ z)) ↔ (x ∨ ¬y)) ∨ ⊥
¬¬((¬x → (y ∨ z)) ↔ (x ∨ ¬y))
((¬x → (y ∨ z)) → (x ∨ ¬y)) ∧ ((¬x → (z ∨ y)) ∨ ¬(¬y ∨ x))
((¬x → (y ∨ z)) ↔ (x ∨ ¬y)) ∧ ((¬x → (z ∨ y)) ↔ (¬y ∨ x))
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