Crowdly
Add to Chrome
Розгляньте код: rdd = sc.parallelize([1, 1, 2, 2, 3]) res = rdd.map(lambd...
✅ The verified answer to this question is available below. Our community-reviewed solutions help you understand the material better.
Розгляньте код:
rdd = sc.parallelize([1, 1, 2, 2, 3])res = rdd.map(lambda x: x + 1).distinct().count()
Яким буде результат
res?0%
0%
100%
0%