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self
with the elements of another queue other
provided as an argument. This may be seen as an in-place queue merging. What would be the worst-case time complexity required to do this operation efficiently? You can assume that n is the length of self
and m is the length of other
.For example, if I had the following queues:self: 1 -> 2 -> 3 -> 4 -> 5 [1 is the front of the queue]
other: 6 -> 7 -> 8 -> 9 -> 10 [6 is the front of the queue]
The result should be:
self: 1 -> 2 -> 3 -> 4 -> 5 -> 6 -> 7 -> 8 -> 9 -> 10 [1 is the front of the queue]
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