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#include <stdio.h> #include <stdlib.h> void f(int * p, int * t) { ...
✅ The verified answer to this question is available below. Our community-reviewed solutions help you understand the material better.
#include <stdio.h>
#include <stdlib.h>
void f(int * p, int * t)
{
// mettre la valeur pointee par p dans la 4ieme case de t
<COMPLETER>
}
int main(void)
{
int i=3;
int t[10];
f(&i,t);
return(0);
}
Compléter la ligne <COMPLETER>
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