Which overload of Foo is selected for each call and why? #include void Foo( int n) { std::cout

Question

Which overload of Foo is selected for each call and why? 
 #include <iostream>   void   Foo( int   n)  { std::cout <<  "int " ; } void   Foo( int * p) { std::cout <<  "ptr " ; }   int   main() {      Foo(NULL);     // (1)      Foo(nullptr);  // (2) }

Answer

(1) int, (2) int - nullptr also converts to int

Answer

(1) ptr, (2) ptr - both are null pointers

Answer

(1) int, (2) ptr - NULL is 0 (type int), nullptr has type nullptr_t

Answer

(1) Compile error, (2) ptr

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Which overload of Foo is selected for each call and why? #include <iostream> ...

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