EmployeeID) est la clé primaire.DepartmentID) est la clé primaire.ProjectID) est la clé primaire.#EmployeeID, #ProjectID) est une clé primaire composite (relation plusieurs-à-plusieurs entre Employee et Project).SELECT COUNT(*) FROM Employee;B) SELECT DepartmentID, COUNT(*) FROM Employee;C) SELECT DepartmentID, COUNT(*) FROM Employee GROUP BY DepartmentID;D) SELECT DepartmentID, COUNT(*) FROM Employee HAVING COUNT(*) > 1;Ja taisnstūra paralēlskaldņa pamata malu garumi ir 9 cm un 12 cm, bet diagonālšķēlums ir kvadrāts, tad paralēlskaldņa augstums ir ... cm.
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Employee (EmployeeID, FirstName, LastName, Email, Phone, HireDate, Salary, #DepartmentID)Department (DepartmentID, DepartmentName, #ManagerID)Project (ProjectID, ProjectName, StartDate, EndDate, Budget)Employee_Project (#EmployeeID, #ProjectID, Role, AssignmentDate)
Which query selects employees whose salary is greater than all employees in department 2?A) SELECT * FROM Employee WHERE Salary > ALL (SELECT Salary FROM Employee WHERE DepartmentID = 2);B) SELECT * FROM Employee WHERE Salary > (SELECT Salary FROM Employee WHERE DepartmentID = 2);C) SELECT * FROM Employee WHERE Salary > ANY (SELECT Salary FROM Employee WHERE DepartmentID = 2);D) SELECT * FROM Employee WHERE Salary IN (SELECT Salary FROM Employee WHERE DepartmentID = 2);