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Imamo standardni problem linearnog programiranja za maksimum zapisan u matričnom obliku: max
Ako s označimo strukturne varijable dualnog problema, kako će izgledati pripadni skup ograničenja?
Sara izrađuje male torbice () i velike torbice (). Tjedno ne može napraviti više od 8 torbica. Koja nejednakost opisuje ovu situaciju?
Donada aquesta sortida a terminal indica quina es la targeta de xarxa integrada a placa mare, resposta haurà de ser 1 o 2:
SORTIDA PER TERMINAL:
Ethernet Controller 1
03:00.0 Ethernet controller: Realtek Semiconductor Co., Ltd. RTL8111/8168/8411 PCI Express Gigabit Ethernet Controller (rev 06)
Subsystem: Gigabyte Technology Co., Ltd Onboard Ethernet
Control: I/O+ Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR+ FastB2B- DisINTx+
Status: Cap+ 66MHz- UDF- FastB2B- ParErr- DEVSEL=fast >TAbort- <TAbort- <MAbort- >SERR- <PERR- INTx-
Latency: 0, Cache Line Size: 64 bytes
Interrupt: pin A routed to IRQ 16
Region 0: I/O ports at d000 [size=256]
Region 2: Memory at f2104000 (64-bit, prefetchable) [size=4K]
Region 4: Memory at f2100000 (64-bit, prefetchable) [size=16K]
Capabilities: <access denied>
Kernel driver in use: r8169
Kernel modules: r8169
05:01.0 Ethernet controller 2: Realtek Semiconductor Co., Ltd. RTL-8100/8101L/8139 PCI Fast Ethernet Adapter (rev 10)
Subsystem: Realtek Semiconductor Co., Ltd. RTL-8100/8101L/8139 PCI Fast Ethernet Adapter
Control: I/O+ Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR+ FastB2B- DisINTx-
Status: Cap+ 66MHz- UDF- FastB2B+ ParErr- DEVSEL=medium >TAbort- <TAbort- <MAbort- >SERR- <PERR- INTx-
Latency: 64 (8000ns min, 16000ns max)
Interrupt: pin A routed to IRQ 18
Region 0: I/O ports at c000 [size=256]
Region 1: Memory at f7110000 (32-bit, non-prefetchable) [size=256]
Expansion ROM at f7100000 [disabled] [size=64K]
Capabilities: <access denied>
Kernel driver in use: 8139too
Kernel modules: 8139cp, 8139too
Què indica l'ordre "ip a" en terminal de debian 12?
Zadani su vektori a i b . Izračunajte ab.
Бинардык издөө алгоритминин ишке ашыруусу берилген:
1. f(int Y[10], int x) {2. int low, high, k;3. low = 0; high = 9;4. do {5. k = (low + high) /2;6. if( Y[k] < x) low = k; else high = k;7. } while(Y[k] != x && low < high);8. if(Y[k] == x) printf ("x табылды") ;9. else printf (" x табылган жок") ;10. } |
Бинардык издөө алгоритминин ишке ашыруусу берилген:
1. f(int Y[10], int x) {2. int low, high, k;3. low = 0; high = 9;4. do {5. k = (low + high) /2;6. if( Y[k] < x) low = k; else high = k;7. } while(Y[k] != x && low < high);8. if(Y[k] == x) printf ("x табылды") ;9. else printf (" x табылган жок") ;10. } |
Koje od danih točaka se nalaze u poluravnini zadanoj nejednadžbom ?