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04-ETTI-L-A3-S1: Instrumentaţie electronică de măsură (Seria G - 2025)
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We consider the 8 bits bipolar DAC similar to that from fig 1. We know =12.8 V and = 15 k. Evaluate the conversion relationship.
Quiz:
Determine value [ k ] to have a DAC resolution = 10 mV
Quiz:
Considering the switching time = 400 ns and OA Slew Rate SR = 8 kV/ms, determine the maximum magnitude , [V], of the sine wave signal with frequency =10 x100 kHz , signal that can be recovered from its samples, without over-slope distortions (the quantization noise is permitted only). It is used the 8 bit number DAC from figure, with resolution = 10 mV.
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What types of DAC error can be minimized by a development engineer who uses a DAC (integrated circuit) in his project ?
What is correct about single slope ADC? (The answer that best suits the question.)
What is correct about sigma - delta ADC ( ADC)? (The answer that best suits the question.)
A bipolar ADC of 9 bits has Vref = 7.68 V and conversion time = 1000 ns. Evaluate the maximum SNR (signal to noise ratio in dB) due quantization process of the analog input signal. We suppose recovering process for the signal, with ideal LPF filter ) :
with values: = 2 V; = 0.5 ; = 500 kHz ; = 100 kHz
Write the result in dB.
Quiz:Suppose the relative errors =20 and =20 , Evaluate the equivalent number of bits for the DAC. (the equivalent resolution bigger than error). In figure, the number of input digital wires is 8;
The answer has to be an integer number!
With 8 bits, bipolar ADC (rounding quantization), having reference voltage VREF = 15.36 V, we perform ADC conversion of UIN = -2770 mV. Determine the binary number from ADC output.
The result must be put in the form: b7b6b5b4b3b2b1b0, where b0 is LSB , and b7 is MSB.
Obs: if leading bits are zeros, you have not to write them ( you should write the number with the leading bit equal to one, even the number appears to be written on smaller number of bits)
Example 1: if the result is b7=1 b6=1, b5=1, b4=1, b3=1, b2=0, b1=0, b0=1
the result must be filled in the following form: 11111001
Example 2: if the result is b7=0 b6=0, b5=0 b4=1, b3=1, b2=0, b1=0, b0=1 you have to fill the b4b3b2b1b0 only
the result must be filled in the following form: 11001