What is the essence of operator overloading? That is, why is it used?

When a function is specified as const as part of its return type, it does not change the host object.

Analyse the following piece of code?

int & newFunction(int y)
{
  int z;
  z = y * y * y;
  return z;
}

Give the rationale for the answer you chose in the previous question (true or false).

Pick all the statements that are correct.

Do you remember a concept called "polymorphism" in OOP? If yes, can you explain it briefly?