Question 4 (cont.)

(e) On the surface bounded by the lower loop, the direction of the magnetic field produced by the current induced in the lower loop is 

Question 4 (cont.)

(f) The direction of the induced current in the lower loop is 

Question 4 (cont.)

When the switch in the upper loop is closed again, the current in upper loop increases quickly from zero to a constant value. While the current in the upper loop is increasing,

(d) The magnetic flux through the lower loop is 

Question 4 (cont.)

(c) The direction of the induced current in the lower loop is 

Question 4 (cont.)

(b) On the surface bounded by the lower loop, the direction of the magnetic field produced by the current induced in the lower loop is

Question 4

Hint for this question: see the magnetic field due to a

current loop in EM Module 3.

The upper and lower loops are horizontal in Figure 3

.

The switch in the upper loop is initially closed. When the switch is opened,

the current I in the

upper loop decreases quickly to zero. While the current in the upper loop is

decreasing,

(a)   

Question 3 (cont.)

(c) The direction of the induced current in the loop is 

Question 3 (cont.)

(b) On the surface bounded by the loop, the direction of the magnetic field produced by the current induced in the loop is 

Question 3

Figure 2 shows a circular conducting loop that lies in the x-y plane, where the +z axis is pointing towards you. There is a constant uniform magnetic field everywhere with direction +z. If the radius of the conducting loop increases with time,

(a) The magnetic flux through the loop is 

Question 2 (cont.)

(c) Calculate the displacement current.