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DataBase Fundamentals new

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Assuming that we have 2 tables - customers and orders:

Which SELECT statement brings both the customers with and those without an order?

select * from customers left join orders on orders.customer_id = customers.customer_id where orders.order_id is not null;

select * from customers left join orders on orders.customer_id = customers.customer_id;

select * from customers join orders on orders.customer_id = customers.customer_id;

select * from customers left join orders on orders.customer_id = customers.customer_id where orders.order_id is null;

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Assuming that we have 2 tables - customers and orders:

Assuming the following query

select * from customers join orders on orders.customer_id = customers.customer_id;

It will not bring the customers that they have never put an order.

True

False

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Assuming that we have 2 tables - customers and orders:

Which of the following queries is correct to count the customers who have put at least one order?

select count(distinct customers.customers_id) from customers join orders on orders.customer_id = customers.customers_id;

select count(*) from customers join orders on orders.customer_id = customers.customer_id;

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Assuming that we have 2 tables - customers and orders:

Assume also that we have 2 customers and the first customer has 3 orders and the second customer has 5 orders. How many rows will the following select query bring?

select * from customers join orders on orders.customer_id = customers.customer_id;

Переглянути це питання

Assuming that we have 2 tables - customers and orders:

Assuming the following query

select * from customers join orders on orders.customer_id = customers.customer_id;

It will not bring the customers that they have never put an order.

True

100%

False

Переглянути це питання

Assuming that we have 2 tables - customers and orders:

Which SELECT statement brings both the customers with and those without an order?

select * from customers left join orders on orders.customer_id = customers.customer_id where orders.order_id is not null;

❌

select * from customers left join orders on orders.customer_id = customers.customer_id;

✅

select * from customers join orders on orders.customer_id = customers.customer_id;

❌

select * from customers left join orders on orders.customer_id = customers.customer_id where orders.order_id is null;

❌

Переглянути це питання

Assuming that we have 2 tables - customers and orders:

Which of the following queries is correct to count the customers who have put at least one order?

select count(distinct customers.customers_id) from customers join orders on orders.customer_id = customers.customers_id;

✅

select count(*) from customers join orders on orders.customer_id = customers.customer_id;

❌

Переглянути це питання

Assuming that we have 2 tables - customers and orders:

Assume also that we have 2 customers and the first customer has 3 orders and the second customer has 5 orders. How many rows will the following select query bring?

select * from customers join orders on orders.customer_id = customers.customer_id;

✅

❌

Переглянути це питання

Assuming that we have 2 tables - customers and orders:

Assuming the following query

select * from customers join orders on orders.customer_id = customers.customer_id;

It will not bring the customers that they have never put an order.

True

100%

False

Переглянути це питання

Assuming that we have 2 tables - customers and orders:

Which SELECT statement brings both the customers with and those without an order?

select * from customers left join orders on orders.customer_id = customers.customer_id where orders.order_id is not null;

❌

select * from customers left join orders on orders.customer_id = customers.customer_id;

✅

select * from customers join orders on orders.customer_id = customers.customer_id;

❌

select * from customers left join orders on orders.customer_id = customers.customer_id where orders.order_id is null;

❌

Переглянути це питання

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