Consider that the number of cycles for the execution of some instructions of a ISA is given by

add --> 5 cycles

xor  --> 2 cycles

lw   --> 2 cycles

sw   --> 5 cycles

multi --> 5 cycles

For the next code:

add $1,$2,$3

lw $4,100($2)

lw $5,100($3)

multi $6,$6,-1

xor  $1,$2,$3

add $8, $2,$13

sw $4,200($3)

sw $14,200($10)

add $11,$12,$13

lw $15,100($3)