The following program does not compile. Identify the reason(s) why. int main()
{ int know = 3;
switch (know)
{
case 3: printf("one
");
break;
case 1+1+1: printf("hi
");
break;
default: printf("bye
");
} return 0; }

Question

The following program does not compile. Identify the reason(s) why. int main() 
 {   int know = 3; 
 switch (know) 
 { 
   case 3:       printf("one
"); 
                 break; 
   case 1+1+1:   printf("hi
"); 
                 break; 
   default:      printf("bye
"); 
 }          return 0;            }

Answer

Duplicate case values are possible, as long as the variable does not match the duplicated case.

Answer

There is a duplicate case value '3'.

Answer

One cannot have an expression as a case value.

Answer

There is no break statement in the default branch.

Crowdly

The following program does not compile. Identify the reason(s) why. int main() ...

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