What will the program output and which C++ feature determines this result? #include class A { public : virtual void Foo() { std::cout

Question

What will the program output and which C++ feature determines this result? #include class A { public : virtual void Foo() { std::cout << "A::Foo" ; } void Bar() { Foo(); } }; class B : public A { public : void Foo() override { std::cout << "B::Foo" ; } }; int main() { A* obj = new B(); obj->Bar(); delete obj; }

Answer

"B::Foo" - virtual dispatch through  this  works even inside a base class method

Answer

Won't compile - Bar() is not declared in class B

Answer

"A::Foo B::Foo" - first call in A, then override in B

Answer

"A::Foo" - Bar() is defined in class A, so Foo() is called as A::Foo

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What will the program output and which C++ feature determines this result? #i...

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