Assume that we have the following Java code:
class Thing {
static double foo = 3.5;
static int bar = 1;

public void baz ( ){
   int bar = 22;
     int x = 0;

     while (x

Question

Assume that we have the following Java code: 
 class  Thing { 
    static   double  foo = 3.5; 
    static int   bar  = 1; 
 
    public void   baz (  ){ 
       int   bar  = 22; 
       int  x = 0;   
 
       while (x < 4){ 
           int   bar  = 99;          
          System.out. println (bar); 
          x += 1; 
   } 
 } 
 What would be the output of the  println  call in the  baz  method?

Accepted Answer

This would generate a compiler error in Java since we cannot create a variable in the while loop in baz that has the same name as a variable outside the while loop in baz.

Answer

The method variables take precedence over the class level variable in this case. But the declaration inside the while loop would be ignored since Java doesn't recognize re-declarations like this. So the println method would display the value 22.

❌

Answer

The class level variable takes precedence in this case,  so the println method would display the value 1.

Answer

The multiple variable declarations create "hidden" variables that hide the outer versions of the variables. So println would display the value 99

Answer

This would generate a compiler error in Java since we cannot create a variable in a local method that has the same name as a class member.

Crowdly

Assume that we have the following Java code: class Thing { static doub...

Хочете миттєвий доступ до всіх перевірених відповідей на moodle.concordia.ca?