14.4 Phases of Matter and Phase Changes
I take 2.0 kg of ice and dump it into 1.0 kg of water and, when equilibrium is reached, I have 3.0 kg of ice at 0 ° C. The water was originally at 0 ° C. The specific heat of water = 1.00 kcal/kg· ° C, the specific heat of ice = 0.50 kcal/kg· ° C, and the latent heat of fusion of water is 80 kcal/kg. The original temperature of the ice was:

Question

14.4 Phases of Matter and Phase Changes 
 I take 2.0 kg of ice and dump it into 1.0 kg of water and, when equilibrium is reached, I have 3.0 kg of ice at 0 ° C. The water was originally at 0 ° C. The specific heat of water = 1.00 kcal/kg· ° C, the specific heat of ice = 0.50 kcal/kg· ° C, and the latent heat of fusion of water is 80 kcal/kg. The original temperature of the ice was:

Answer

one or two degrees below 0 ° C.

Answer

− 80 ° C.

Answer

− 120 ° C.

Answer

The whole experiment is impossible.

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14.4 Phases of Matter and Phase Changes I take 2.0 kg of ice and dump it into ...

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