Given the following pseudocode, derive the recurrence relation that represents its time complexity. def fibonacci(n):
if (n==0 or n==1):
return n
return fibonacci(n - 1) + fibonacci(n - 2) Let b and c represent constant values. What is the base case and recurrence step?

Question

Given the following pseudocode, derive the recurrence relation that represents its time complexity.  def fibonacci(n):
    if (n==0 or n==1):
        return n 
    return fibonacci(n - 1) + fibonacci(n - 2) Let b and c represent constant values. What is the base case and recurrence step?

Answer

T(n) = T(n-1) + T(n-2) + c
T(1) = T(0) = b

Answer

T(n) = T(n-2) + c
T(1) = T(0) = b

Answer

T(n) = T(n-1) + c
T(1) = T(0) = b

Answer

T(n) = T(n-1) + T(n-2) + c
T(0) = T(1) = n

Crowdly

Given the following pseudocode, derive the recurrence relation that represents ...

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