logo

Crowdly

Browser

Додати до Chrome

Questions Bank (1279545 total)

The rate of reaction between two reactants A and B decreases by a factor of

4 if the concentration of reactant B is doubled. The order of reaction with

respect to reactant B is:

0%
0%
0%
0%
Переглянути це питання

The conversion of molecules X and Y follows second-order kinetics. If the concentration

of X is increased to three times, how will it affect the rate of formation of

Y?

Переглянути це питання

The rate of a chemical reaction doubles for every 10°C rise of temperature.

If the temperature is raised by 50°C, the rate of the reaction increases by

about:

0%
0%
0%
0%
Переглянути це питання

For the reaction: 2A +

B

3C + D 

Which of the

following does not express the reaction rate?

0%
0%
0%
Переглянути це питання

Consider a reaction, aG +

bH → Products. When

concentration of both the reactants G and H is doubled, the rate increases by

eight times. However, when the concentration of G is doubled keeping the

concentration of H fixed, the rate is doubled. The overall order of the

reaction is:

0%
0%
0%
0%
Переглянути це питання

Which of the following statement for order of the reaction is not correct?

Переглянути це питання

A reaction involving

two different reactants can never be:

Переглянути це питання

For the reaction N2O5(g)

Image failed to load
2NO2(g) + 1/2O2

(g)

the value of rate of disappearance of N

2O5

 is given

as 6.25 m 10

–3 mol L–1 s–1

. The rate

of formation of NO

2 and O2

 is given

respectively as:

0%
0%
0%
0%
Переглянути це питання

In a reaction, B→Product, rate is doubled when the concentration of 

is

doubled, and rate increases by a factor of 8 when the concentrations of both

the reactants (

and B

) are doubled, rate law for the

reaction can be written as:

Переглянути це питання

In

the reaction:

 BrO3

 (aq)

+ 5Br

 (aq) + 6H+
Image failed to load
3Br2 (l) + 3H2O(l) 

The rate of

appearance of bromine (Br

2

) is related to the rate of disappearance

of bromide ions as

Переглянути це питання