Питання | Сторінка 141657

Under the 5-state process model, processes with IDs 3, 7, 15, 20 and 24 are executing on a system. They arrived in the ready queue in the order they are listed, starting with process 3. The processes do not fail and do not make I/O requests. The short-term scheduler uses the following preemptive priority scheduling algorithm (processes with larger priority numbers have higher priority):

- the process with the highest priority runs on the CPU (FCFS is used, in case of a tie);

- a process has priority 0 when it first enters the ready queue;

- the priorities of all processes in the ready queue continuously decrease at the same rate;

- the priority of the process running on the CPU also continuously decreases, but more slowly than the priorities for processes in the ready queue.

Based only on this information, what is the order in which the processes finish executing?

First 3, then 7, then 15, then 20 and finally 24

First 3, then 15, then 7, then 24 and finally 20

First 24, then 20, then 15, then 7 and finally 3

First 3, then 24, then 7, then 20 and finally 15

First 24, then 3, then 20, then 7 and finally 15

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