z_1 = 2\text{cis}(\dfrac{\pi}{4}) and z_2 = 3\text{cis}(\dfrac{2\pi}{3}) 

z_1 = 6\text{cis}(\dfrac{2\pi}{3}) and z_2=\text{cis}(\dfrac{3\pi}{4}) 

z_1 =\text{cis}(\dfrac{\pi}{3}) and z_2 = 6\text{cis}(\dfrac{3\pi}{4}) 

z_1 =3\text{cis}(\dfrac{\pi}{3}) and z_2 = 2\text{cis}(\dfrac{\pi}{2}) 

The function has two critical points.

The graph of the function is concave up at its local maximum.

The graph of the function is concave up at its global maximum.

The graph of the function is concave down at its local maximum.

The derivative is zero at two values of x, one being a global extremum.

The graph of the function is concave down at its local minimum.

x^{\cos\,x-1}\cos\,x-x^{\cos\,x}\sin\,x\,\text{ln}\,x

x^{\cos\,x-1}\cos\,x+x^{\cos\,x}\text{ln}\,x

x^{\cos\,x-1}\cos\,x

x^{\cos\,x-1}\cos\,x-x^{\cos\,x}\,\sin\,x

x^{\cos\,x}\text{ln}(\cos\,x)

|x^2+2x|

|x^2+2|

e^{\sin\,x}

2x\cos(x+1)

\mathbb{R}\backslash\{0,4\}

\{0\}

\{4\}

\{0,4\}

\mathbb{R}\backslash\{0\}

\mathbb{R}

\mathbb{R}\backslash\{4\}

{z:z-1 > 1}

{z:|z| \geq 1}

{z:|z-1| \geq 1}

{z:|z+1| > 1}

{z:|z-1| > 1}

{z:1\leq |z| \leq 3}

{z:1< |z| < 3}

{z:1\leq |z| < 3}

{z:1\leq z \leq 3}

{z:1 < z < 3}