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338.001/2/4/5/8/22/23/24/25/26/27/28/29, VL / UE Logic, Martina Seidl et al., 2026W
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Given formula ψ := (x) ∧ (¬y ∨ ¬z) ∧ (¬x ∨ y ∨ z)
The propositional formula (a ∨ ¬a) ∧ (b ∨ ¬b) ∧ (c ∨ ¬c) ∧ (d) ∧ (¬d) ∧ (e ∨ ¬e) ∧ (f ∨ ¬f) ∧ (g ∨ ¬g) ∧ (h ∨ ¬h) ∧ (i ∨ ¬i) ∧ (j ∨ ¬j) is ...
The propositional formula (a ∨ ¬a) ∧ (b ∨ ¬b) ∧ (c ∨ ¬c) ∧ (d ∨ ¬d) ∧ (e ∨ ¬e) ∧ (f ∨ ¬f) ∧ (g ∨ ¬g) ∧ (h ∨ ¬h) ∧ (i ∨ ¬i) ∧ (j ∨ ¬j) is ...
Which assignment satisfies which formula?
Given the propositional formula ψ := ((a ∨ ¬b ∨ c) ∧ (¬a ∨ b ∨ c) ∧ (a ∨ ¬b ∨ ¬c) ∧ (¬a ∨ ¬b ∨ c) ∧ (¬a ∨ b ∨ ¬c)).
Which of the following assignments satisfy ψ?
A model of a propositional formula is a satisfying assignment.
Consider the formula ((a ∨ b) ∧ (c ∨ d) ∧ (e ∨ f ∨g)). How many different variable assignments are possible?
How many models does the empty clause have?
An empty conjunction is ...
The empty clause is ...