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Soit la poutre suivante de longueur 3m. AB = 2m ; BC = 1m.
Torseur AB:
Nx = 0 ; Ty = -3,33 KN ; Mfz = 10 KNm
Torseur BC:
Nx = 20 KN ; Ty = -3,33 KN ; Mfz = 3,33.x KNm
Nx = 20 KN ; Ty = -3,33 KN ; Mfz = -3,33.(3-x) KNm
Nx = 0 ; Ty = -3,33 KN ; Mfz = 3,33.x KNm
Nx = 0 ; Ty = -3,33 KN ; Mfz = -3,33.(3-x) KNm
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