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Soit la structure suivante. AB = 3m ; BC = 2m. Le couple en C est autour de z.
Calculer les torseurs de cohésion.
Torseur AB:
Nx = 30 KN ; Ty = -30 KN ; Mfz = -20 - 30.2 -10.(3-x).(3-x)/2 KNm
Torseur BC:
Tx = 30 KN ; Ny = 0 ; Mfz = -20 KNm
Nx = 30 KN ; Ty = -30 KN ; Mfz = -20 - 30.2 KNm
Nx = -30 KN ; Ty = -10.(3-x) KN ; Mfz = -20 + 30.2 -10.(3-x).(3-x)/2 KNm
Tx = -30 KN ; Ny = 0 ; Mfz = -20 + 30.(2-y) KNm
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