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Нехай ДДНФ функції F (x, y, z) містить доданок . З цього виходить що
F(x,y,z)=1 при x=0,y=0,z=1
F(x,y,z)=1 при x=1,y=1,z=0
F(x,y,z)=0 при x=0,y=0,z=1
F(x,y,z)=0 при x=1,y=1,z=0
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