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Soit la poutre suivante de longueur 3m. AB = BC = CD = 1m.
Torseur AB:
Nx = 0 ; Ty = 10.x KN ; Mfz = -10.x.x/2 KNm
Torseur BC:
Nx = 0 ; Ty = 5 -10.(3-x) KN ; Mfz = 10+5.(2-x) -10.(3-x).(3-x)/2 KNm
Torseur CD:
Nx = 0 ; Ty = -10.(3-x) KN ; Mfz = 10 -10.(3-x).(3-x)/2 KNm
Nx = 0 ; Ty = 10.x KN ; Mfz = 0 KNm
Nx = 0 ; Ty = 5 -10.(3-x) KN ; Mfz = 10 KNm
Nx = 0 ; Ty = -10.(3-x) KN ; Mfz = 10 KNm
Nx = 10 KN ; Ty = 10.x KN ; Mfz = 0 KNm
Nx = 10 KN ; Ty = 5 -10.(3-x) KN ; Mfz = 10 KNm
Nx = 10 KN ; Ty = -10.(3-x) KN ; Mfz = 10 KNm
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