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Дано u = 1, елемент адитивної групи G(р)+ = G(13)+ . Оберіть вираз для генерування елемента 8 mod 13 тієї ж групи.
8 = (1+1+1+1+1)
8 = (24 • 1) / 3
8 = (16 • 1) / 2
8 = (1+1+1+1+1+1+1+1)
8 = 8 • 1
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