Ze wzoru Taylora mamy dla x>0 : \frac{2}{x^2}+x=b_0+b_1(x-2)+b_2(x-2)^2+b_3...
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Ze wzoru Taylora mamy dla x>0:
\frac{2}{x^2}+x=b_0+b_1(x-2)+b_2(x-2)^2+b_3(x-2)^3+R_4(\theta, x).
Ile wynosi b_3?
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