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Soit la structure suivante. AB = 3m ; BC = 2m. Le couple en C est autour de z.
Calculer les torseurs de cohésion.
Torseur AB:
Nx = 0 ; Ty = -10.(3-x) KN ; Mfz = -20 -10.(3-x).(3-x)/2 KNm
Torseur BC:
Tx = 0 ; Ny = 0 ; Mfz = -20 KNm
Nx = 0 ; Ty = 0 ; Mfz = -20 KNm
Nx = 0 ; Ty = -10.(3-x) KN ; Mfz = -20 KNm
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