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Нехай F (x, y, z) = 1 при x = 1, y = 0, z = 1. З цього випливає, що ДДНФ функції...

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Нехай F (x, y, z) = 1 при x = 1, y = 0, z = 1. З цього випливає, що ДДНФ функції містить доданок:

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