Sean \(S=\mathcal{L}\big((1,2,0),(1,-1,1)\big)\quad\quad \text{y}\quad \quad ...
✅ The verified answer to this question is available below. Our community-reviewed solutions help you understand the material better.
Sean
\(S=\mathcal{L}\big((1,2,0),(1,-1,1)\big)\quad\quad \text{y}\quad \quad T\,\equiv\quad \left.\begin{array}{rcl}x&=&\lambda+2\mu\\(4mm] y&=&\lambda+\mu\
en Entonces una base del subespacio es
0%
0%
0%