Q6. Find the output gain in terms of input signals
For the ideal op-amp given below, what is V_{out} , if the input waveform is sinusoidal with the form A ext{sin}(\omega t) , where A0 and \omega0 . Assume the diode D1 is a precision ideal diode so that it is fully conducting with no resistance for positive voltage and open circuit for reverse voltage, both applied from anode to cathode.

Question

Q6. Find the output gain in terms of input signals 
 For the ideal op-amp given below, what is   V_{out} , if the input waveform is sinusoidal with the form   A 	ext{sin}(\omega t) , where   A>0  and   \omega>0 . Assume the diode D1 is a precision ideal diode so that it is fully conducting with no resistance for positive voltage and open circuit for reverse voltage, both applied from anode to cathode.

Answer

V_{out} = A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) >0   , and   V_{out} = -A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) < 0

Answer

V_{out} = -A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) >0   , and   V_{out} = (1 - \frac{R_2}{R_1})A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) < 0

Answer

V_{out} = (1 + \frac{R_2}{R_1})A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) >0   , and   V_{out} =- (1 + \frac{R_2}{R_1})A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) < 0

Answer

V_{out} = (1 - \frac{R_2}{R_1})A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) >0   , and   V_{out} = (1 + \frac{R_2}{R_1})A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) < 0

Answer

V_{out} = A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t)>0   , and   V_{out} = (1 + \frac{R_2}{R_1})A 	ext{sin}(\omega t)  when   A 	ext{sin}(\omega t) < 0

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Q6. Find the output gain in terms of input signals For the ideal op-amp given ...

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