If “enable” is high 20% of the time , and the code below is synthesized, which of the following will have the absolutely lowest power consumption.

Question

If  “enable” is high 20% of the time , and the code below is synthesized, which of the following will have the absolutely lowest power consumption.

Accepted Answer

wire [31:0] A, B, D; 
    reg [31:0] E, F, G; 
    always@(posedge clock) 
        begin 
        	E <= AA * BB; 
        end 
    assign AA = enable ? A : 0; 
    assign BB = enable ? B : 0;

Answer

wire [31:0] A, B, D; 
    reg [31:0] E, F, G; 
    always@(posedge clock) 
        begin 
        	if (enable) E <= A * B; 
        	else E <= 0 * 0; 
        end

Answer

wire [31:0] A, B, D, MultIn1, MultIn2, MultOut; 
    reg [31:0] E, F, G; 
    always@(posedge clock) 
        begin 
        	MultIn1 = enable ? A : 0; 
                MultIn2 = enable ? B : 0; 
                E = MultIn1 * MultIn2; 
      end

Answer

wire [31:0] A, B, D; 
    reg [31:0] E, F, G; 
    always@(posedge clock) 
        begin 
        	if (enable) E <= A * B; 
        end

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If “enable” is high 20% of the time , and the code below is synthesized, which ...

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