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Dynamique des solides

Dynamique des solides

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Soit deux bases $B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z})$ B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z}) et $B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})$ B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})

Calculer la dérivée suivante :

$\left. \frac{d \overrightarrow{i}}{dt} \right|_1$ \left. \frac{d \overrightarrow{i}}{dt} \right|_1

$\dot{\alpha} \overrightarrow{i}$ \dot{\alpha} \overrightarrow{i}

$- \dot{\alpha} \overrightarrow{i}$ - \dot{\alpha} \overrightarrow{i}

$- \dot{\alpha} \overrightarrow{k}$ - \dot{\alpha} \overrightarrow{k}

$\overrightarrow{0}$ \overrightarrow{0}

$\dot{\alpha} \overrightarrow{k}$ \dot{\alpha} \overrightarrow{k}

$- \dot{\alpha} \overrightarrow{j}$ - \dot{\alpha} \overrightarrow{j}

$\dot{\alpha} \overrightarrow{j}$ \dot{\alpha} \overrightarrow{j}

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Soit deux bases $B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z})$ B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z}) et $B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})$ B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})

Calculer la dérivée suivante :

$\left. \frac{d \overrightarrow{x}}{dt} \right|_2$ \left. \frac{d \overrightarrow{x}}{dt} \right|_2

$\dot{\alpha} \overrightarrow{y}$ \dot{\alpha} \overrightarrow{y}

$\overrightarrow{0}$ \overrightarrow{0}

$- \dot{\alpha} \overrightarrow{x}$ - \dot{\alpha} \overrightarrow{x}

$\dot{\alpha} \overrightarrow{z}$ \dot{\alpha} \overrightarrow{z}

$\dot{\alpha} \overrightarrow{x}$ \dot{\alpha} \overrightarrow{x}

$- \dot{\alpha} \overrightarrow{z}$ - \dot{\alpha} \overrightarrow{z}

$- \dot{\alpha} \overrightarrow{y}$ - \dot{\alpha} \overrightarrow{y}

View this question

Soit deux bases $B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z})$ B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z}) et $B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})$ B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})

Calculer la dérivée suivante :

$\left. \frac{d \overrightarrow{k}}{dt} \right|_1$ \left. \frac{d \overrightarrow{k}}{dt} \right|_1

$\dot{\alpha} \overrightarrow{i}$ \dot{\alpha} \overrightarrow{i}

$- \dot{\alpha} \overrightarrow{i}$ - \dot{\alpha} \overrightarrow{i}

$- \dot{\alpha} \overrightarrow{k}$ - \dot{\alpha} \overrightarrow{k}

$\overrightarrow{0}$ \overrightarrow{0}

$\dot{\alpha} \overrightarrow{k}$ \dot{\alpha} \overrightarrow{k}

$- \dot{\alpha} \overrightarrow{j}$ - \dot{\alpha} \overrightarrow{j}

$\dot{\alpha} \overrightarrow{j}$ \dot{\alpha} \overrightarrow{j}

View this question

Soit deux bases $B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z})$ B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z}) et $B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})$ B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})

Calculer la dérivée suivante :

$\left. \frac{d \overrightarrow{i}}{dt} \right|_2$ \left. \frac{d \overrightarrow{i}}{dt} \right|_2

$\dot{\alpha} \overrightarrow{i}$ \dot{\alpha} \overrightarrow{i}

$- \dot{\alpha} \overrightarrow{i}$ - \dot{\alpha} \overrightarrow{i}

$- \dot{\alpha} \overrightarrow{k}$ - \dot{\alpha} \overrightarrow{k}

$\overrightarrow{0}$ \overrightarrow{0}

$\dot{\alpha} \overrightarrow{k}$ \dot{\alpha} \overrightarrow{k}

$- \dot{\alpha} \overrightarrow{j}$ - \dot{\alpha} \overrightarrow{j}

$\dot{\alpha} \overrightarrow{j}$ \dot{\alpha} \overrightarrow{j}

View this question

Soit deux bases $B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z})$ B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z}) et $B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})$ B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})

Calculer la dérivée suivante :

$\left. \frac{d \overrightarrow{i}}{dt} \right|_1$ \left. \frac{d \overrightarrow{i}}{dt} \right|_1

$\dot{\alpha} \overrightarrow{i}$ \dot{\alpha} \overrightarrow{i}

$- \dot{\alpha} \overrightarrow{i}$ - \dot{\alpha} \overrightarrow{i}

$- \dot{\alpha} \overrightarrow{k}$ - \dot{\alpha} \overrightarrow{k}

$\overrightarrow{0}$ \overrightarrow{0}

$\dot{\alpha} \overrightarrow{k}$ \dot{\alpha} \overrightarrow{k}

$- \dot{\alpha} \overrightarrow{j}$ - \dot{\alpha} \overrightarrow{j}

$\dot{\alpha} \overrightarrow{j}$ \dot{\alpha} \overrightarrow{j}

View this question

Soit deux bases $B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z})$ B_1 ( \overrightarrow{x}, \overrightarrow{y}, \overrightarrow{z}) et $B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})$ B_2 ( \overrightarrow{i}, \overrightarrow{j}, \overrightarrow{k})

Calculer la dérivée suivante :

$\left. \frac{d \overrightarrow{x}}{dt} \right|_2$ \left. \frac{d \overrightarrow{x}}{dt} \right|_2

$\dot{\alpha} \overrightarrow{y}$ \dot{\alpha} \overrightarrow{y}

$\overrightarrow{0}$ \overrightarrow{0}

$- \dot{\alpha} \overrightarrow{x}$ - \dot{\alpha} \overrightarrow{x}

$\dot{\alpha} \overrightarrow{z}$ \dot{\alpha} \overrightarrow{z}

$\dot{\alpha} \overrightarrow{x}$ \dot{\alpha} \overrightarrow{x}

$- \dot{\alpha} \overrightarrow{z}$ - \dot{\alpha} \overrightarrow{z}

$- \dot{\alpha} \overrightarrow{y}$ - \dot{\alpha} \overrightarrow{y}

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Quelle est l'expression $\overrightarrow{\Omega} ( 0/1 )$ \overrightarrow{\Omega} ( 0/1 ) ?

$\dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0$ \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0

$\dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0$ \dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0

$\dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_1$ \dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_1

$\dot{\psi} \overrightarrow{j}{}_1$ \dot{\psi} \overrightarrow{j}{}_1

$\dot{\beta} \overrightarrow{i}{}_0$ \dot{\beta} \overrightarrow{i}{}_0

$- \dot{\alpha} \overrightarrow{k}{}_1$ - \dot{\alpha} \overrightarrow{k}{}_1

$\dot{\alpha} \overrightarrow{k}{}_1$ \dot{\alpha} \overrightarrow{k}{}_1

View this question

Quelle est l'expression $\overrightarrow{\Omega} ( 2/0 )$ \overrightarrow{\Omega} ( 2/0 ) ?

$\dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0$ \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0

$\dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0$ \dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0

$\dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_1$ \dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_1

$\dot{\psi} \overrightarrow{j}{}_1$ \dot{\psi} \overrightarrow{j}{}_1

$\dot{\beta} \overrightarrow{i}{}_0$ \dot{\beta} \overrightarrow{i}{}_0

$- \dot{\alpha} \overrightarrow{k}{}_1$ - \dot{\alpha} \overrightarrow{k}{}_1

$\dot{\alpha} \overrightarrow{k}{}_1$ \dot{\alpha} \overrightarrow{k}{}_1

View this question

Quelle est l'expression $\overrightarrow{\Omega} ( 3/0 )$ \overrightarrow{\Omega} ( 3/0 ) ?

$\dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0$ \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0

$\dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0$ \dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0

$\dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_1$ \dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_1

$\dot{\psi} \overrightarrow{j}{}_1$ \dot{\psi} \overrightarrow{j}{}_1

$\dot{\beta} \overrightarrow{i}{}_0$ \dot{\beta} \overrightarrow{i}{}_0

$- \dot{\alpha} \overrightarrow{k}{}_1$ - \dot{\alpha} \overrightarrow{k}{}_1

$\dot{\alpha} \overrightarrow{k}{}_1$ \dot{\alpha} \overrightarrow{k}{}_1

View this question

Quelle est l'expression $\overrightarrow{\Omega} ( 1/0 )$ \overrightarrow{\Omega} ( 1/0 ) ?

$\dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0$ \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0

$\dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0$ \dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_0 + \dot{\beta} \overrightarrow{i}{}_0

$\dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_1$ \dot{\psi} \overrightarrow{j}{}_1 + \dot{\alpha} \overrightarrow{k}{}_1

$\dot{\psi} \overrightarrow{j}{}_1$ \dot{\psi} \overrightarrow{j}{}_1

$\dot{\beta} \overrightarrow{i}{}_0$ \dot{\beta} \overrightarrow{i}{}_0

$- \dot{\alpha} \overrightarrow{k}{}_1$ - \dot{\alpha} \overrightarrow{k}{}_1

$\dot{\alpha} \overrightarrow{k}{}_1$ \dot{\alpha} \overrightarrow{k}{}_1

View this question

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