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ECE3161 Analogue Electronics - MUM S2 2025

ECE3161 Analogue Electronics - MUM S2 2025

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Q1. Op-Amp Output

What is the $V_{\text{out}}$ V_{\text{out}} of this circuit assuming that the ideal OpAmp does not saturate for the conditions given.

$V_{in}$ V_{in}

$\frac{(R_1+ R_2)V_{in}}{R_2}$ \frac{(R_1+ R_2)V_{in}}{R_2}

$-\frac{(R_1+ R_2)V_{in}}{R_1R_2}$ -\frac{(R_1+ R_2)V_{in}}{R_1R_2}

$\frac{(R_1+ R_2)V_{in}}{R_1}$ \frac{(R_1+ R_2)V_{in}}{R_1}

$\frac{R_1R_2V_{in}}{(R_1 + R_2)}$ \frac{R_1R_2V_{in}}{(R_1 + R_2)}

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Q7. Determine the transfer function of the circuit

In the angular frequency domain, $\omega$ \omega, determine the transfer function $H[\omega]$ H[\omega] of the circuit below.

$H[\omega] = \frac{R_1}{(R_1 +R_2) - iCR_1R_2 \omega}$ H[\omega] = \frac{R_1}{(R_1 +R_2) - iCR_1R_2 \omega}

$H[\omega] = \frac{CR_1R_2\omega}{(R_1 +R_2) + iCR_1R_2 \omega}$ H[\omega] = \frac{CR_1R_2\omega}{(R_1 +R_2) + iCR_1R_2 \omega}

$H[\omega] = \frac{R_2R_1}{(R_1 +R_2) - iCR_1R_2 \omega}$ H[\omega] = \frac{R_2R_1}{(R_1 +R_2) - iCR_1R_2 \omega}

$H[\omega] = \frac{R_1}{(R_1 +R_2) + iCR_1R_2 \omega}$ H[\omega] = \frac{R_1}{(R_1 +R_2) + iCR_1R_2 \omega}

$H[\omega] = \frac{R_2}{(R_1 +R_2) + iCR_1R_2 \omega}$ H[\omega] = \frac{R_2}{(R_1 +R_2) + iCR_1R_2 \omega}

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Q6. Superposition Theorem

Use the superposition theorem to find the current I_x in the circuit below.

-0.279 A

0.05 A

0.277 A

-0.05 A

0.23 A

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Q5. Superposition Theorem

Use the superposition theorem to find I_0 in the circuit below.

5.5 A

-1.5 A

-2.5 A

2.5 A

-5.5 A

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Q4. Thevenin's Equivalent Circuit

Find the Thevenin's equivalent circuit for the following circuit. Assume i > 0 and v > 0.

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Q3. Thevenin's Equivalent Circuit

Find the Thevenin's equivalent circuit for the following circuit.

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Q2. Norton’s Equivalent Circuit

Find I_0 using Norton’s theorem.

-3.444 A

-2.444 A

4.333 A

2.444 A

3.444 A

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Q1. Thevenin's Equivalent Circuit

Find the Thevenin's equivalent circuit for the following circuit.

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Q2. Determine the RMS value of noise voltage

Equivalent noise bandwidth of a single pole filter is given by $\frac{\pi}{2}\omega_{3dB}$ \frac{\pi}{2}\omega_{3dB}, where $\omega_{3dB}$ \omega_{3dB} is the $3\text{dB}$ 3\text{dB} bandwidth of the single pole filter in rad/s. Suppose a spectrum analyzer measures a noise voltage spectral density of $1\mu\text{V}/\sqrt{\text{Hz}}$ 1\mu\text{V}/\sqrt{\text{Hz}} before a single pole filter with $3\text{dB}$ 3\text{dB} bandwidth of $5\text{MHz}$ 5\text{MHz}. What is the RMS value of this noisy signal over an infinite bandwidth?

1.4 mV

2 mV

2.8 mV

2.5 mV

1 mV

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Q10. Determine the small signal differential gain

What is the small signal differential gain $v_{od}/v_{id}$ v_{od}/v_{id} for the differential pair below at temperature 300K. Assume both transistor are identical.

15

23

12

9.4

19

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