ECE3161 Analogue Electronics - MUM S2 2025 Course Materials & Test Answers | learning.monash.edu

Q1. Find the output waveform

If the input to the ideal op-amp circuit below is $A\text{sin}(\omega t)+ B\text{cos}(2 \omega t)$ A\text{sin}(\omega t)+ B\text{cos}(2 \omega t) where A and B are constants, and $\omega$ \omega is the angular frequency, what is the output waveform?

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$V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) )+ H(2\omega) B \text{cos}(2\omega t + \theta(2\omega))$ V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) )+ H(2\omega) B \text{cos}(2\omega t + \theta(2\omega)) given that $H(\omega)e^{j\theta(\omega)} = \frac{R_2}{R_1(1 + j\omega C_1R_2)}$ H(\omega)e^{j\theta(\omega)} = \frac{R_2}{R_1(1 + j\omega C_1R_2)}

$V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) )+ H(\omega) B \text{cos}(2\omega t + \theta(\omega))$ V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) )+ H(\omega) B \text{cos}(2\omega t + \theta(\omega)) given that $H(\omega)e^{j\theta(\omega)} = \frac{R_2}{R_1(1 + j\omega C_1R_2)}$ H(\omega)e^{j\theta(\omega)} = \frac{R_2}{R_1(1 + j\omega C_1R_2)}

$V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) ) - H(\omega) B \text{cos}(2\omega t + \theta(\omega))$ V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) ) - H(\omega) B \text{cos}(2\omega t + \theta(\omega)) given that $H(\omega)e^{j\theta(\omega)} = \frac{R_1R_2}{(1 + j\omega C_1R_1)}$ H(\omega)e^{j\theta(\omega)} = \frac{R_1R_2}{(1 + j\omega C_1R_1)}

$V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) )+ H(2\omega) B \text{cos}(2\omega t + \theta(2\omega))$ V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) )+ H(2\omega) B \text{cos}(2\omega t + \theta(2\omega)) given that $H(\omega)e^{j\theta(\omega)} = \frac{R_1}{R_2(1 + j\omega C_1R_1)}$ H(\omega)e^{j\theta(\omega)} = \frac{R_1}{R_2(1 + j\omega C_1R_1)}

$V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) )+ H(\omega) B \text{cos}(2\omega t + \theta(\omega))$ V_{out}(t) = H(\omega) A\text{sin}(\omega t + \theta(\omega) )+ H(\omega) B \text{cos}(2\omega t + \theta(\omega)) given that $H(\omega)e^{j\theta(\omega)} = \frac{R_1}{R_2(1 + j\omega C_1R_1)}$ H(\omega)e^{j\theta(\omega)} = \frac{R_1}{R_2(1 + j\omega C_1R_1)}

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ECE3161 Analogue Electronics - MUM S2 2025

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