Looking for ECE212s (UG2023) - Introduction to Electronics (39309) test answers and solutions? Browse our comprehensive collection of verified answers for ECE212s (UG2023) - Introduction to Electronics (39309) at lms.eng.asu.edu.eg.
Get instant access to accurate answers and detailed explanations for your course questions. Our community-driven platform helps students succeed!
Consider a bridge rectifier fed by a 50 Hz sinusoid with a peak value of 7.6 V. Assume ideal diode model. Let the load resistance be 14.7 kOhm. For a peak-to-peak ripple less than 100 mV, the filter capacitor must be greater than ..... uF (micro Farad).
The diode forward drop is used as a voltage regulator in the circuit shown below. Assume VON = 0.7 V. If VS = 10.5 V, then VOUT is approximately equal to ..... V.
Consider a bridge rectifier circuit and assume ideal diode model. If the input amplitude is equal to 8.5 V, then the PIV is equal to ..... V.
A sine wave is applied to a dc restorer circuit. Assume ideal diode model. If the maximum voltage at the output is equal to 7.4 V, then the amplitude of the sine wave is equal to ..... V.
The diode forward drop is used as a voltage regulator in the circuit shown below. If VS = 10.7 V, and RL = 2.8 kOhm, then the load current is approximately equal to ..... mA.
Assume VON = 0.7 V.
Consider a bridge rectifier circuit with a filter capacitor and assume ideal diode model. If the input amplitude is 5.6 V and the load current is zero, then the peak-to-peak output ripple is equal to ..... V.
Assume ideal diode model. If a sine wave with input amplitude equal to 6.3 V is applied to a doubler circuit, the absolute output voltage |Vout| is equal to ..... V.
Assume VT = 26 mV, VON = 0.7, VS = 6.8 V, and R = 8.8 kOhm. The small signal resistance of the diode is equal to ..... Ohm.
Consider a bridge rectifier circuit fed by a 50 Hz sinusoid with a peak value of 10.9 V. Assume VON = 0.7 V. Let the load resistance be 5.3 kOhm. The maximum current flowing in the load is equal to ..... mA.
The diode forward drop is used as a voltage regulator in the circuit shown below. Assume VON = 0.7 V. If VS = 9.4 V, then VOUT is approximately equal to ..... V.