Crowdly
Add to Chrome
CONTROL SYSTEMS EEE F242 ECE F242 INSTR F242
Looking for CONTROL SYSTEMS EEE F242 ECE F242 INSTR F242 test answers and solutions? Browse our comprehensive collection of verified answers for CONTROL SYSTEMS EEE F242 ECE F242 INSTR F242 at quantaaws.bits-goa.ac.in.
Get instant access to accurate answers and detailed explanations for your course questions. Our community-driven platform helps students succeed!
Consider the root locus for a unity-gain negative feedback system having the characteristic equation
, where k denotes the compensator gain of the forward path transfer function.
Let thetadep (in degrees) be the value of the angle of departure of the root locus branch starting from the pole at
The value of thetadep (in degrees) =
Note: Write your answer such that 0 <= thetadep<= 360 (degrees).
Consider the root locus for a unity-gain negative feedback system having the characteristic equation
, where k denotes the compensator gain of the forward path transfer function.
Let k = kBA > 0 be the value of the gain at the break-away point.
The value of sBA =
Consider a unity-gain negative feedback system with
We have magnitude of G1(s)=12.6 at s=0.
Design a lag compensator Gc1(s) = (s+zc1)/(s+pc1) so as reduce the steady-state error by a factor of 10, as compared to the steady-state error of the uncompensated closed-loop system.
Calculate the ratio zc1/pc1 =
Consider the root locus for a unity-gain negative feedback system having the characteristic equation
, where k denotes the compensator gain of the forward path transfer function.
Let thetaarriv (in degrees) be the value of the angle of arrival of the root locus branch arriving at the zero at
State the value of thetaarriv (in degrees) =
Note: Write your answer such that 0 <= thetaarriv<= 360 (degrees).
Consider a unity-gain negative feedback system with
Design a PD compensator Gc(s) = kc (s+zc) so as to place one of the closed-loop poles at s=s* = -12.6 +j12.6 .
We have, the magnitude of G(s)=0.01 at s=s*.
Also, the angle of degrees at s=s*.
The value of zc =
Consider a unity-gain negative feedback system with
Design a PD compensator Gc(s) = kc (s+zc) so as to place one of the closed-loop poles at s=s* = -12.6 +j12.6 .
We have, the magnitude of G(s)=0.01 at s=s*.
Also, the angle of degrees at s=s*.
The value of kc =
Consider the root locus for a unity-gain negative feedback system having the characteristic equation
, where k denotes the compensator gain of the forward path transfer function.
Let k = kmarginal > 0 be the value of the gain at which the branches of the root locus intersect the imaginary axis.
The value of kmarginal =
Consider the root locus for a unity-gain negative feedback system having the characteristic equation
, where k denotes the compensator gain of the forward path transfer function.
Let k = kBA > 0 be the value of the gain at the break-away point.
The value of kBA =
Consider the unit step response of a negative feedback closed-loop system with the forward path transfer function . Here, the compensator gain in the forward path is denoted by
Determine the steady-state error (ess1 ) corresponding to the unit step response of the (that is, with
The value of the settling time ess1 =
A unity-gain feedback system has as the forward path transfer function. Obtain the unit step response for the closed-loop system. Calculate the peak time (t ) for the unit step response.
The value of the peak time (tp) =